(X^2+5x)=(4x)+110

Solution for (X^2+5x)=(4x)+110 equation:

(X^2+5X)=(4X)+110

We move all terms to the left:

(X^2+5X)-((4X)+110)=0

We get rid of parentheses

X^2+5X-4X-110=0

We add all the numbers together, and all the variables

X^2+X-110=0

a = 1; b = 1; c = -110;
Δ = b2-4ac
Δ = 12-4·1·(-110)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-21}{2*1}=\frac{-22}{2}
=-11
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+21}{2*1}=\frac{20}{2}
=10
$